# Can U Solve This Upsc?

## Which is the correct answer for 1 3 5 7 9 11 13?

The mean of 1, 3, 5, 7, 9, 11, 13 is 7. We can easily solve this problem by following the given steps.

## Can you add 3 odd numbers to get 30?

It is not possible because according to rule of mathematics sum of two odd numbers is always even, take any example. 3+5=8. 7+13=20 etc and then sum of one odd and one even number is always odd number hence in no combination odd and even can turn up to be even which is 30.

## Who is Gaurav Agrawal?

IAS officer. Ex-investment banker @ Citi. IIT IIM graduate.

## How do you solve 3 boxes that equal 30?

The answer to the “select 3 balls to equal 30” puzzle is 6, 11 and 13.

## What is the answer of 33×33 33 33 -: 0?

According to the rule of BODMAS, we will have to do the divide first and we know that we are dividing any number for that matter by zero we get infinity. So, when we are dividing 33×33+33-33 by 0 then the answer will be infinity. Hence, the value of 33×33+33-33 is infinity.

## What is the rule for 1 3 5 7 9?

The sequence that is given to us is 1, 3, 5, 7, 9, … a5 – a4 = 9 – 7 = 2. Hence, from the above simplification we can see that the common difference is 2. Therefore, the general term for the sequence 1, 3, 5, 7, 9, . . . is 2n – 1.

## Is 11.5 an odd number?

Odd numbers can’t be divided by 2 and leave a whole number. Any odd number divided by 2 will leave a fraction. So, 17 ÷ 2 = 8.5, and 23 ÷ 2 = 11.5. All odd numbers will end in 1, 3, 5, 7, or 9.

## Can you select 3 watermelons?

Well, several people have posted answers to the question. “Not possible because all are odd numbers and sum of three odd numbers can never be an even number (30),” wrote an individual.

## Is 30000 a odd number?

30000 is not an odd number but an even number. It is completely divisible by 2.

## Who is the youngest UPSC topper?

Ansar Shaikh: He is the youngest IAS Officer in India. Ansar, a 2016 batch IAS Officer, currently serves in the West Bengal Cadre. Tina Dabi: A 2015 UPSC IAS Topper needs no introduction.